Whenever we develop Web or Mobile Applications, there is always a need for sending emails for various reasons through the developed platform. Some of the reasons why we need to integrate email service are:
You can find a few use cases here.
There are multiple services around through which we can integrate Email Services into our platform. This article will cover the integration of one of the most popular emailing services Twilio’s SendGrid.
Related read: Automating Database Translation in Django REST Framework Using gTranslate Library
Prerequisites
This article assumes that you’ve theoretical and practical knowledge of Python, Django Rest Framework, and implementing third party libraries in it.
Preface
This article is going to be covering how to set-up a SendGrid account and implement a SendGrid Emailing Service at the server-side.
We will follow the steps below in order:-
Now let’s start the integration process.
Setting Up A SendGrid Account
For getting started with sending email through SendGrid, we will require an API key which will be used in our Django SendGrid integration. We need to create a SendGrid account by Signing up or by Logging in to your SendGrid account. In the left sidebar, select Settings > API keys > Create API Key.
Enter a name for your API key. Choose the API key access whichever is suitable for your requirement. Full Access permissions give the key the ability to perform all the necessary email sending functions. If you prefer to create a key that has very specific permissions, then select “Restricted Access” and configure your access as needed.
When you click the “Create & View” button you will be presented with your key. This key will never be shown again, so you need to click on it to copy it to the clipboard, and then paste it in a secure document so that you can use it later. If you lose your key, you will need to generate a brand new one. Once you have saved your key, you can click the “Done” button.
Note: Do not share your SendGrid API Key with anyone as it may be misused.
Designing A Dynamic Transactional Template
For creating a dynamic template, In the left sidebar, select Email API > Dynamic Templates > Create a Dynamic Template. Enter a name for your template and click on “Save”.
To begin with, editing your new template, click on “Add Version”. Then Select a Design template as per your requirements or you can create new blank templates, Lastly, you need to Select an Editor (how you will be editing the template by Code Editor or by Design Editor)
Now that you have the version we can start editing the template as per our need.
Starting With The Development Process
1. Installation
pip3 install sendgrid
2. Adding required values in settings.py file for PayU
# Twilio Sendgrid API key SENDGRID_API_KEY = 'YOUR SENDGRID API KEY' # setting default email for sending email through sendgrid DEFAULT_FROM_EMAIL = "YOUR SENDER MAIL ID"
3. Creating a class-based view for sending email using Mail helper Class
import sendgrid from sendgrid.helpers.mail import (Mail, Email,Personalization) from python_http_client import exceptions from twilio_sendgrid_integration.settings import DEFAULT_FROM_EMAIL, SENDGRID_API_KEY sg = sendgrid.SendGridAPIClient(SENDGRID_API_KEY) class MailSenderAPIView(GenericAPIView): def send_mail(self, template_id, sender, recipient, data_dict): mail = Mail() mail.template_id = template_id mail.from_email = Email(sender) personalization = Personalization() personalization.add_to(Email(recipient)) personalization.dynamic_template_data = data_dict mail.add_personalization(personalization) try: response = sg.client.mail.send.post(request_body=mail.get()) except exceptions.BadRequestsError as e: print("INSIDE") print(e.body) exit() print(response.status_code) print(response.body) print(response.headers) def post(self, request): recepient_email = request.data['recepient_email'] subject = request.data['subject'] fullname = request.data['fullname'] body = request.data['body'] template_id = "d-1772e8ac6b5442e68975394ea71a4957" sender = DEFAULT_FROM_EMAIL data_dict = {"subject": subject, "user_name": fullname, "body": body} MailSenderAPIView.send_mail(self, template_id, sender, recepient_email, data_dict) return Response({"status_code": status.HTTP_200_OK, "message": "Mail sent successfully."})
4. Creating endpoint for the created Class view for sending an email
from django.conf.urls import url from .views import MailSenderAPIView urlpatterns = [ url('sendTemplateEmail', MailSenderAPIView.as_view(), name="mail-sender"), ]
You can find the whole implementation here.
Shubham is a Lead Python developer with 3+ years of experience. He is very passionate about his work. He is always eager to learn new programming skills and technologies and looking for new ways to optimize the development process. His areas of expertise are in Building Machine Learning models, Creating REST APIs in Django/Flask, Web Scraping and Writing Automation Scripts for businesses.
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